Proving the Convolution Formula: Integral Equations

  • Thread starter Thread starter icystrike
  • Start date Start date
  • Tags Tags
    Property Urgent
icystrike
Messages
444
Reaction score
1

Homework Statement



\int_{0}^{1} \int_{0}^{1} (xy) dx dy = [\int_{0}^{1} (x) dx] [\int_{0}^{1} (y) dy]

Its use to prove the convolution formula..


Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
It's just standard separating multiple integrals, you could write the same thing with xy replaced by f(x)f(y).
 
Tangent87 said:
It's just standard separating multiple integrals, you could write the same thing with xy replaced by f(x)f(y).

But why is that so? Is it because the region of integration is rectangular?
Referring to Fubini Theorem
 
icystrike said:
But why is that so? Is it because the region of integration is rectangular?
Referring to Fubini Theorem

No the region of integration does not have to be rectangular, it will work whenever the integral converges/exists, as you say Fubini's theorem: http://en.wikipedia.org/wiki/Fubini's_theorem
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top