Proving the Value of a Complex Integral Involving Cosecant and the Unit Circle

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SUMMARY

The integral ∫ csc(z)dz/z evaluates to zero when C is the unit circle around the origin, as established in Arthur A. Hauser's Complex Variables textbook, Chapter 5, Problem 5.42. The proof involves demonstrating that ∫0 to 2π csc(eiθ) dθ equals zero, leveraging the symmetry properties of the integrand. The discussion emphasizes avoiding the Cauchy Integral Formula for this proof, suggesting a focus on the inherent characteristics of the cosecant function.

PREREQUISITES
  • Understanding of complex variables and integrals
  • Familiarity with the properties of the cosecant function
  • Knowledge of symmetry in mathematical functions
  • Basic concepts of contour integration
NEXT STEPS
  • Study the properties of the cosecant function in complex analysis
  • Explore symmetry and anti-symmetry in integrands
  • Review contour integration techniques without the Cauchy Integral Formula
  • Investigate other integrals involving trigonometric functions over the unit circle
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Students and professionals in mathematics, particularly those studying complex analysis, as well as educators seeking to enhance their understanding of integral properties and proofs.

benjamin198
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I need help to solve this problem from Complex variables, Arthur A. Hauser, Ch. 5. pag. 122. Problem 5.42
show that ∫ csc(z)dz/z = 0
where C is the unit circle around the origin.


Solve it without using The Cauchy Integral Formula...
 

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hi benjamin198! :smile:

you need to prove ∫0 csc(e) dθ = 0

perhaps there's something symmetric, or anti-symmetric, about the integrand? :wink:
 

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