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## Homework Statement

A 100 kg man dangles a 50 kg mass from the end of a rope. If he stands on a frictionless surface and hangs the mass over a cliff with a pulley, the tension in the rope will be:

(A) 250 N

(B) 333 N

(C) 500 N

(D) 667 N

The answer is B but I am having a difficult time setting this one up.

## Homework Equations

F=ma

## The Attempt at a Solution

Okay, so we know that for the man, T = ma because he is on a frictionless surface and the block is mg = T+ma.

Some others have posted this problem on this site but I need clarification for the second equation listed above. I cannot combine these equations because the masses are different. So, what I did was alter the equations as

man: T=2ma

block: mg = T+ma

substituting gives me: mg = 2ma +ma

therefore, g = 3a and a = 3.33 m/s

But when I go back to my "altered" equations to solve for T, I get 667 N which is wrong. Anyone know what I am doing wrong here?