Pulses Superposition: After 5s & 1cm/s Velocity

  • Thread starter Thread starter tanzerino
  • Start date Start date
AI Thread Summary
Two pulses are moving towards each other on a string at a velocity of 1 cm/s. After 5 seconds, the leading edge of each pulse will have moved 5 cm, resulting in an overlap. The concept of superposition is applied by stacking the overlapping sections of the pulses visually. Participants confirm the accuracy of the drawn representation and the method used to illustrate the superposition. This discussion emphasizes understanding pulse behavior and superposition principles in wave mechanics.
tanzerino
Messages
48
Reaction score
0
1. Two pulses are traveling towards each other at 1 cm/s on a long string at t = 0 s, as shown below.
,after t=5s and velcoity=1cm/s what would be the shape of the pulses:



http://img21.imageshack.us/img21/7654/homeworkk.png
 
Last edited by a moderator:
Physics news on Phys.org
Where will the leading edge of each pulse be after 5 s? Draw a picture of each pulse and, where they overlap, stack them up like boxes. That's superposition.
 
so this means number second one?
i drew both pulses and stacked the overlaping and left the others alone.
 
I would say you are correct.
 
Thanks a lot for your help.:smile:
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top