Pushing a lawn mower, total force exerted?

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A person pushes a 13.0 kg lawn mower at a constant speed with a force of 77.0 N at a 49.0° angle. To accelerate the mower from rest to 1.8 m/s in 2.0 seconds, the required acceleration is calculated to be 0.81 m/s². The user initially calculated the force needed as 10.5 N but was confused about incorporating the retarding force of -50.5 N. After some discussion, the user found clarity through another problem and expressed gratitude for the assistance. The conversation highlights the challenges of calculating net forces in physics problems involving acceleration and retarding forces.
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Homework Statement


A person pushes a 13.0 kg lawn mower at constant speed with a force of 77.0 N directed along the handle, which is at an angle of θ = 49.0° to the horizontal.

Calculate the force the person must exert on the lawn mower to accelerate it from rest to 1.8 m/s in 2.0 seconds with a retarding force of -50.5 N in the x direction.

Homework Equations


Using LaTeX Code: v^2 = v_0^2 + 2 a \\Delta x I found a = 0.81 m/s^2



The Attempt at a Solution


Using the acceleration of 0.81 m/s^2 times 13 kg I get F = 10.5 N, now I think I'm supposed to add the retarding force, but 61 N isn't correct.
Did I miss something?
Found the retarding force by finding the Fpcos(49) = 50.5 (in the x direction) Fp = 77.0 N.
Beyond that I'm lost. Please help
 
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Nevermind, another problem helped me out, thank you! More will come!
 
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