Puzzle: Who Pays More in the Beer Hall?

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    Beer Puzzle
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The discussion revolves around a brain teaser involving eleven friends at a beer hall, where six sit at table A and five at table B. Each person orders drinks for their respective tables, leading to confusion about why a person at table A ends up paying more than someone at table B despite having more payers. The key point is that table A orders more expensive drinks and consumes more, resulting in each person at table A paying for six drinks while those at table B pay for only five. Some participants in the discussion express surprise at the difficulty others have in grasping the solution, suggesting that assumptions about synchronized ordering and drinking contribute to the confusion. The conversation highlights the importance of understanding the dynamics of group orders and consumption in solving the puzzle.
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This story surprisingly puzzles some people:

Eleven friends go into a beer hall. Six of them sit at table A and five of them sit at table B. Each of the eleven orders one round for his own table. Now table A has more payers, but a person at table A ends up paying more than a person at table B.

?
 
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The guys at table A ordered more expensive drinks, where's the brain teaser?
 
Chen said:
The guys at table A ordered more expensive drinks, where's the brain teaser?

NO!
The guys on B run off from the bill.

Another is that the waiter didn't catch the order from the guys around B, and, in frustration, they left to see "Van Helsing" instead.
 
quartodeciman said:
This story surprisingly puzzles some people:

Eleven friends go into a beer hall. Six of them sit at table A and five of them sit at table B. Each of the eleven orders one round for his own table. Now table A has more payers, but a person at table A ends up paying more than a person at table B.

?

Sure, why shouldn't he. Each guy on table A pays for 6 drinks while each dude at B pays for only 5.

This is true if all drinks cost the same and the waiter was a patient, vampire fearing man.

Whassamattah ?
 
People who fail this test end up hopeless drunks.

(What seems to throw some people off is that table A is consuming more beer than table B)
:smile:
 
Oh dear..
(Besides, "Van Helsing" was an atrociously bad movie..)
 
Gokul43201 said:
Sure, why shouldn't he. Each guy on table A pays for 6 drinks while each dude at B pays for only 5.

This is true if all drinks cost the same and the waiter was a patient, vampire fearing man.

Whassamattah ?

That's why a wise person buys a pitcher for a group, not individual drinks :biggrin:
 
Table A people all pay more, but also get more beer.

Table A people buy 6 beers and drink 6 beers.

Table B people buy 5 beers and drink 5 beers.

Very easy if you haven't been drinking a lot.

Njorl
 
it is really strange how come so many people here are stupid enough to not be able to solve this problem.
 
  • #10
I suspect that many people at first assume (without warrant) that the two table-fulls are somehow ordering and drinking in complete synchrony.

It is probably important to emphasize that table A has more payers (without drawing attention to more drinks ordered) to pull this puzzle off.
 
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