A Q: Scalar Boundary Condition & U(1) Isometry - Lewkowycz & Maldacena

craigthone
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I have a simple question about Lewkowycz and Maldacena's paper [PLAIN]http://arxiv.org/abs/1304.4926v2[/PLAIN]
http://arxiv.org/abs/1304.4926v2

In section 2, they consider the scalar field in BTZ background ground and require boundary condition of the scalar field,

$\phi \sim e^{i\tau}$ . This boudary condition breaks the U(1) isomentry of BTZ background. My question is what kinds of boudary condition will respect the U(1) isometry? $\phi$does not depend on $ \tau$?
 
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The answer is YES. Respecting U(1) symmetry of phi means independence of tau coordinate.
 
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