Q vxB Magnetic Force: Reconciling Two Situations

In summary, there is a situation where a charge q with velocity v along the x axis experiences a force F=qvB along the z axis due to a uniform magnetic field B along the y axis. However, in a reference frame moving at velocity v along the x axis, F=qvB=0 and there is no force on the particle. This discrepancy can be resolved by incorporating special relativity into the theory of magnetic forces.
  • #1
eltodesukane
97
19
there is something I don't understand
maybe someone can tell me

- a charge q has velocity v along the x axis
- there is a uniform magnetic field B along the y axis
- so the particule experience a force F=qvB along the z axis

Now consider the same situation in a reference frame moving at velocity v along the x axis.
Now F=qvB=0 and there is no force on the particule.

What am I missing?
How to reconcile those situation?
 
Physics news on Phys.org
  • #2

Related to Q vxB Magnetic Force: Reconciling Two Situations

1. What is Q vxB magnetic force?

Q vxB magnetic force refers to the force that is exerted on a charged particle moving through a magnetic field. It is a vector quantity that is determined by the charge of the particle, its velocity, and the strength and direction of the magnetic field.

2. How is Q vxB magnetic force different from other types of forces?

Unlike other forces, Q vxB magnetic force only acts on charged particles and is dependent on both the particle's charge and its velocity. It is also a perpendicular force, meaning it acts at a 90 degree angle to the direction of the particle's velocity.

3. How is Q vxB magnetic force calculated?

The magnitude of Q vxB magnetic force can be calculated using the equation F = qvBsinθ, where q is the charge of the particle, v is its velocity, B is the strength of the magnetic field, and θ is the angle between the particle's velocity and the direction of the magnetic field.

4. What is the relationship between Q vxB magnetic force and magnetic fields?

Q vxB magnetic force is directly proportional to the strength of the magnetic field. This means that as the strength of the magnetic field increases, the force exerted on the charged particle also increases.

5. How does Q vxB magnetic force reconcile two situations?

Q vxB magnetic force reconciles two situations by explaining the relationship between charged particles moving through a magnetic field. It helps to explain the circular motion of charged particles in a magnetic field and why the direction of this motion is always perpendicular to the magnetic field lines.

Similar threads

I Question on the Lorentz force: Why is the force not F=q(v×B) = F=qv×qB
    • Electromagnetism
Replies
8
Views
1K
I Question on Hall Effect and magnetic force
    • Electromagnetism
Replies
2
Views
943
I Rate of work done by F on charge carrier with average velocity v
    • Electromagnetism
Replies
6
Views
1K
I The vector math of relative motion of wire-loop & bar magnet
    • Electromagnetism
Replies
1
Views
1K
A proof that magnetic forces do no work?
    • Electromagnetism
2
Replies
36
Views
3K
What is the induced magnetic force on this closed current loop?
    • Introductory Physics Homework Help
Replies
12
Views
281
Electric potential energy between charge and moving magnet
    • Electromagnetism
Replies
7
Views
1K
Magnetic Force and Frame of Reference
    • Electromagnetism
Replies
3
Views
2K
Magnetic Lorentz Force: Questions & Answers
    • Electromagnetism
Replies
4
Views
1K
Is the Lorentz magnetic force verified?
    • Electromagnetism
Replies
25
Views
2K

Hot Threads

Recent Insights

Back
Top