QM: Expectation value of raising and lowering operator

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SUMMARY

The discussion focuses on deriving the expectation value of the raising and lowering operators in quantum mechanics, specifically the equation \(\langle j,m_z \mid J_-J_+ \mid j,m_z \rangle = h^2[ j(j+1) - m_z(m_z+1)]\). The operators are defined as \(J_- = J_x - iJ_y\) and \(J_+ = J_x + iJ_y\). The solution attempts to simplify \(J_-J_+\) to \(J^2 - J_z^2\) but identifies a missing term in the derivation. The discussion highlights the critical point that \(J_x\) does not commute with \(J_y\), which affects the calculations.

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barefeet
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Homework Statement


Using
<br /> J^2 \mid j,m_z \rangle = h^2 j(j+1) \mid j,m_z \rangle <br />
<br /> J_z \mid j,m_z \rangle = hm_z \mid j,m_z \rangle <br />

Derive that :
<br /> \langle j,m_z \mid J_-J_+ \mid j,m_z \rangle = h^2[ j(j+1) - m_z(m_z+1)]<br />

Homework Equations


<br /> J_- = J_x - iJ_y<br />
<br /> J_+ = J_x + iJ_y<br />

The Attempt at a Solution


<br /> J_-J_+ = (J_x- iJ_y)(J_x + iJ_y) = J_x^2 + J_y^2 = J^2 - J_z^2<br />

<br /> \langle j,m_z \mid J_-J_+ \mid j,m_z \rangle = \langle j,m_z \mid J^2 - J_z^2 \mid j,m_z \rangle = h^2[ j(j+1) - m_z^2]<br />

Apparently I am missing a term here but I don't know where it should come from. I thought this should be true
<br /> J_z^2 \mid j,m_z \rangle = J_zJ_z \mid j,m_z \rangle = h^2m_z^2 \mid j,m_z \rangle <br />
(Note: h is hbar everywhere )
 
Physics news on Phys.org
You are assuming that ##J_x## commutes with ##J_y## when computing ##J_-J_+##. This is not the case.
 
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