QM Measurements - probability, expectation value

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duckie
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Homework Statement



What are the possible results and their probabilities for a system with l=1 in the angular momentum state u = [tex]\frac{1}{\sqrt{2}}[/tex](1 1 0)? What is the expectation value?
((1 1 0) is a vertical matrix but I can't see how to format that)

Homework Equations




The Attempt at a Solution



[tex]L_{z} = \hbar[/tex](1,0,-1) for l=1 where (1,0,-1) represents the block diagonal... again, not sure how to do matrices on here :rolleyes:

By saying [tex]L_{z}u = \lambda u[/tex] and just comparing I have results for lambda of +1, 0, -1.

I know probability is the modulus of <a|u> squared where a is a corresponding eigenvector... but I'm getting a bit lost somehow. Normally I'm ok with these, but this time I'm just not sure on what to do next.
Any hints would be greatly appreciated :smile:
 
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duckie said:

Homework Statement



What are the possible results and their probabilities for a system with l=1 in the angular momentum state u = [tex]\frac{1}{\sqrt{2}}[/tex](1 1 0)? What is the expectation value?
((1 1 0) is a vertical matrix but I can't see how to format that)

I assume you are asked the possible outcomes and their probabilities for a measurement of [itex]L_z[/itex]? You haven't actually said which observable your measuring in this problem statement.

There are several environments you can use to display matrices and column vector in [itex]\LaTeX[/itex] (see my sig). To see how to generate the following image, just click on it.

[tex]u=\frac{1}{\sqrt{2}}\begin{pmatrix} 1 \\ 1 \\ 0\end{pmatrix}[/tex]


[tex]L_{z} = \hbar[/tex](1,0,-1) for l=1 where (1,0,-1) represents the block diagonal... again, not sure how to do matrices on here :rolleyes:

Again, click on the following image:

[tex]L_z=\hbar\begin{pmatrix} 1 & 0 & 0 \\ 0 & 0 & 0 \\ 0 & 0 & -1\end{pmatrix}[/tex]

By saying [tex]L_{z}u = \lambda u[/tex] and just comparing I have results for lambda of +1, 0, -1.

Shouldn't your eigenvalues have units of angular momentum ?:wink:

I know probability is the modulus of <a|u> squared where a is a corresponding eigenvector... but I'm getting a bit lost somehow. Normally I'm ok with these, but this time I'm just not sure on what to do next.
Any hints would be greatly appreciated :smile:

Well, what are the eigenvectors [itex]|a\rangle[/itex] of [itex]L_z[/itex]?
 
gabbagabbahey said:
I assume you are asked the possible outcomes and their probabilities for a measurement of [itex]L_z[/itex]? You haven't actually said which observable your measuring in this problem statement.
Urgh sorry, yes I meant for a measurement of [itex]L_z[/itex]... Late night :frown:

gabbagabbahey said:
Shouldn't your eigenvalues have units of angular momentum ?:wink:
And yes, I meant 0, [tex]\pm\hbar[/tex].


gabbagabbahey said:
Well, what are the eigenvectors [itex]|a\rangle[/itex] of [itex]L_z[/itex]?

Right, I think they're [tex]\begin{pmatrix} 1 \\ 0 \\ 0\end{pmatrix}[/tex] for [tex]\lambda=\hbar[/tex], [tex]\frac{1}{\sqrt{3}}\begin{pmatrix} 1 \\ 1 \\ 1\end{pmatrix}[/tex] for [tex]\lambda=0[/tex], and [tex]\begin{pmatrix} 0 \\ 0 \\ 1\end{pmatrix}[/tex] for [tex]\lambda=-\hbar[/tex].

Are those right?
 
duckie said:
Right, I think they're [tex]\begin{pmatrix} 1 \\ 0 \\ 0\end{pmatrix}[/tex] for [tex]\lambda=\hbar[/tex], [tex]\frac{1}{\sqrt{3}}\begin{pmatrix} 1 \\ 1 \\ 1\end{pmatrix}[/tex] for [tex]\lambda=0[/tex], and [tex]\begin{pmatrix} 0 \\ 0 \\ 1\end{pmatrix}[/tex] for [tex]\lambda=-\hbar[/tex].

Are those right?

I'd choose [tex]\begin{pmatrix}0 \\ 1 \\ 0\end{pmatrix}[/tex] for [itex]\lambda=0[/itex], so that your eigenvectors are an orthonormal set.

What does that make the probability of measuring zero for [itex]L_z[/itex]? How about [itex]\hbar[/itex]? And [itex]-\hbar[/itex]?