Quadratic application question what was the jets speed from Bangkok to Tokyo

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Discussion Overview

The discussion revolves around a quadratic application problem involving the speed of a jet flying between Bangkok and Tokyo. Participants explore the relationship between distance, speed, and time, particularly focusing on how to formulate the equations based on the given conditions of speed reduction and time difference.

Discussion Character

  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant presents a quadratic equation to determine the jet's speed, suggesting that the speed from Bangkok to Tokyo is represented as \(v\) and the return speed as \(v - 200\).
  • Another participant questions the formulation of the equations, suggesting that the return speed should be represented as \(v + 200\) instead of \(v - 200\), based on the context of the problem.
  • There is a discussion about the two roots obtained from the quadratic equation, with a participant noting that only the positive root is meaningful for speed.

Areas of Agreement / Disagreement

Participants express differing views on the correct formulation of the speed equations, indicating a lack of consensus on whether the return speed should be \(v + 200\) or \(v - 200\). The discussion on how to interpret the roots of the quadratic equation also reflects uncertainty.

Contextual Notes

Participants have not resolved the assumptions regarding the formulation of the speed equations, and there are unresolved steps in the mathematical reasoning leading to the quadratic equation.

Wild ownz al
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Hey this Quadratic application question is giving me trouble.

A jet flew from Tokyo to Bangkok, a distance of 4800km. On the return trip, the speed was decreased by 200km/h. If the difference in the times of the flights was 2 hours, what was the jets speed from Bangkok to Tokyo?

Just need the formula for the Jets speed and I should be fine with the rest.

This was my guess: 4800 = (x-200)(-2x)
 
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Wild ownz al said:
Hey this Quadratic application question is giving me trouble.

A jet flew from Tokyo to Bangkok, a distance of 4800km. On the return trip, the speed was decreased by 200km/h. If the difference in the times of the flights was 2 hours, what was the jets speed from Bangkok to Tokyo?

Just need the formula for the Jets speed and I should be fine with the rest.

This was my guess: 4800 = (x-200)(-2x)

Hello, and welcome to MHB! (Wave)

I've moved your question to its own thread.

I would use the fact that time is distance per average speed. Let distances be measured in km and time in hrs. Let \(v\) be the plane's speed from Bangkok to Tokyo.

$$t-2=\frac{4800}{v+200}$$

$$t=\frac{4800}{v}$$

Now, these equations imply:

$$t=\frac{4800}{v+200}+2=\frac{4800}{v}$$

Multiply through by \(v(v+200)\):

$$4800v+2v(v+200)=4800(v+200)$$

Distribute after dividing through by 2, then collect like terms and arrange in standard form:

$$v^2+200v-480000=0$$

Factor:

$$(v+800)(v-600)=0$$

Discarding the negative root, we find:

$$v=600$$

Does this make sense?
 
AMAZING you are brilliant. Thank you :)
 
Wild ownz al said:
AMAZING you are brilliant. Thank you :)

If the plane's speed is "decreased" by 200km/h then shouldn't it be (v - 200) instead of (v + 200)?

Also if you ended up with two roots how do you know which one is the planes speed?
 
Wild ownz al said:
If the plane's speed is "decreased" by 200km/h then shouldn't it be (v - 200) instead of (v + 200)?

The first equation represents the first leg of the journey, from Tokyo to Bangkok. But, \(v\) represents the speed on the second leg, the return trip, where the speed has been decreased by 200. And so the speed on the first leg must be \(v+200\).

Wild ownz al said:
Also if you ended up with two roots how do you know which one is the planes speed?

Speed, in order to have any meaning, must be positive (it is a magnitude like distance), and so we discard the negative root.
 

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