Quadratic equations: Perimeter and Area fencing dimensions

AI Thread Summary
The discussion focuses on solving a problem involving an enclosure built with 280 m of fencing and an area of 2800 m². The dimensions are expressed in terms of length (L) and width (W), with the perimeter equation being 2L + 2W = 280 and the area equation being L * W = 2800. Participants clarify that manual measurements are not needed for this problem. The quadratic formula is referenced for solving the resulting equations. The goal is to find the dimensions of the enclosure to the nearest tenth.
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Homework Statement


The following enclosure is built using 280 m of fencing. If the enclosure has a total area of 2800 m2, what are the dimensions to the nearest tenth?

Homework Equations


x = \frac{-b ± \sqrt{b^{2}-4ac}}{2a}


The Attempt at a Solution


Please note that the 3/2w and 5/2w were measurements I did with a ruler. I am pretty sure that is wrong since this question is not suppose to require manual measurements.

03.24.2013-15.15.png
 
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Assume the enclosure is L long and W wide.

What is the amount of fencing used, in terms of W and L?
What is the area of the enclosure, in terms of W and L?
 

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