Quadratic Equations: Find Integral Values of 'k' for 2 Rational Solutions

AI Thread Summary
To determine the integral values of 'k' for which the quadratic equation 2x^2 + kx - 4 = 0 has two rational solutions, the discriminant must be a perfect square. The discriminant is expressed as k^2 + 32. Setting n^2 = k^2 + 32 leads to the equation n^2 - k^2 = 32, which factors to (n - k)(n + k) = 32. The discussion focuses on finding the integer pairs (n, k) that satisfy this equation, with the condition that n must be greater than k. The exploration of potential values for k starts from 2 and involves checking how high k needs to be evaluated for valid solutions.
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Homework Statement


Find the number of integral values of 'k' for which the quadratic equation 2x^2 +kx - 4=0 will have two rational solutions.


Homework Equations



d=(b^2- 4ac)^(1/2)

The Attempt at a Solution



If discriminant is a perfect square, then the roots will be rational and unequal. but for how many values of 'k' starting from 2 itself will I check th discriminant to be a perfect square?
 
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The discriminant is k^2+32. So k^2+32=n^2 where n is an integer. n^2-k^2=32. But n^2-k^2=(n-k)*(n+k). How high do you need to check?
 
n is at least k+1, so n^2-k^2 >= (k+1)^2 - k^2 = 2k + 1
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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