A Quantum Anti-Zeno Effect and Decay Rates

Aakash Sunkari
Messages
13
Reaction score
1
Hey everyone,

I have a question about how "viable" the Quantum Anti-Zeno Effect (AZE) is at lowering decay rates in radioactive nuclei. We know that the AZE can, in fact, reduce the half life of radioactive isotopes, but there seems to be a barrier to that.

AZE states that decay can be accelerated by frequent observations. Of course, in a decaying nucleus, we can "shoot" photons at it. But here's where the problem begins.

If the measurements were infrequent you could implement such a scheme in a fairly straightforward fashion. However, because the measurements must be frequent, then they also have to be short in time. The issue then becomes that a pulse cannot be arbitrarily short in time and arbitrarily specially narrow because of the time-energy uncertainty relation as shown here:
qtKraYAR7RKG36QWAUiK9uHmy5XJW2sfbmalLR1XzLBT81cyiqFAqQIf3utvRdnXXuOSHW8smbhZR0JpvbUrkKsSUkOKkmvB.png

Therefore by trying to interrogate the system very quickly, you must let it interact with pulses that are very broad in energy, and which hence can perturb the system in such a fashion (e.g. coupling to other decay channels) that the net effect is an increase in the rate of decay.

My question is, how realistic is it that shooting photons can increase the decay rate of an isotope? If it is realistic, by how much? (Is there an equation for this?)

If shooting photons is an unrealistic method for frequent observation, what would be a more realistic method?
 

Attachments

  • qtKraYAR7RKG36QWAUiK9uHmy5XJW2sfbmalLR1XzLBT81cyiqFAqQIf3utvRdnXXuOSHW8smbhZR0JpvbUrkKsSUkOKkmvB.png
    qtKraYAR7RKG36QWAUiK9uHmy5XJW2sfbmalLR1XzLBT81cyiqFAqQIf3utvRdnXXuOSHW8smbhZR0JpvbUrkKsSUkOKkmvB.png
    22.8 KB · Views: 622
Physics news on Phys.org
The energy scale of the decay is MeV, you would probably need MeV photons - but then you might directly induce the decays with the photons.
 
Toponium is a hadron which is the bound state of a valance top quark and a valance antitop quark. Oversimplified presentations often state that top quarks don't form hadrons, because they decay to bottom quarks extremely rapidly after they are created, leaving no time to form a hadron. And, the vast majority of the time, this is true. But, the lifetime of a top quark is only an average lifetime. Sometimes it decays faster and sometimes it decays slower. In the highly improbable case that...
I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
Back
Top