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tomothy
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1. Radial and angular distribution functions for an orbital
Find the most probable value of theta and r for a 2pz orbital
[itex]\psi _{2p_{z}} = N \textrm{cos}(\theta) r exp (-r/2)[/itex] in units of [itex]a_0[/itex]
Most probable r is when [itex] \textrm{d/d}r (P(r))=0 \Rightarrow r_\textrm{max} = 4[/itex] where [itex] P(r)=r^2 |R(r)|^2[/itex]
The most probable value of theta is the maximum of the theta function squared weighted by sin(theta), the volume of a thin conical shell.
[itex]P(\theta)=\textrm{sin}(\theta) |\Theta (\theta)|^2 \Rightarrow \theta_\textrm{max} = \textrm{arcsin}(\pm1/\sqrt{3})[/itex]
Cheers.
Find the most probable value of theta and r for a 2pz orbital
Homework Equations
[itex]\psi _{2p_{z}} = N \textrm{cos}(\theta) r exp (-r/2)[/itex] in units of [itex]a_0[/itex]
The Attempt at a Solution
Most probable r is when [itex] \textrm{d/d}r (P(r))=0 \Rightarrow r_\textrm{max} = 4[/itex] where [itex] P(r)=r^2 |R(r)|^2[/itex]
The most probable value of theta is the maximum of the theta function squared weighted by sin(theta), the volume of a thin conical shell.
[itex]P(\theta)=\textrm{sin}(\theta) |\Theta (\theta)|^2 \Rightarrow \theta_\textrm{max} = \textrm{arcsin}(\pm1/\sqrt{3})[/itex]
Cheers.