Quantum Mechanics - Lowering Operator

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Homework Help Overview

The discussion revolves around the properties of lowering and raising operators in quantum mechanics, specifically focusing on the relationship between a lowering operator \( A \) and its corresponding raising operator \( A^\dagger \). Participants are exploring the mathematical implications of these operators and their commutation relations.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss defining functions in terms of the raising operator and using commutation relations to explore the properties of the lowering operator. There are attempts to derive relationships involving derivatives and commutators, with some members expressing confusion about the next steps in their reasoning.

Discussion Status

The discussion is ongoing, with participants seeking clarification on specific steps and methods. Some guidance has been provided regarding the use of commutation relations and the application of the Leibniz product rule, but there is no explicit consensus on the next steps or the overall approach.

Contextual Notes

There is mention of language barriers affecting comprehension, and some participants have noted the need for clearer explanations of the mathematical concepts involved. Additionally, the original poster has not fully articulated the commutation relations, which may be contributing to the confusion.

izzmach
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Homework Statement


let A be a lowering operator.

Homework Equations


Show that A is a derivative respects to raising operator, A†,

A=d/dA†

The Attempt at a Solution


I start by defining a function in term of A†, which is f(A†) and solve it using [A , f(A†)] but i get stuck after that. Can someone please explain briefly what i should do in the next step?
 
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##A_+|n> = |n-1> \, , \, A_-|n+1> = |n> ## so
$$ A_+\,A_-\, |n> = |n> \,\Rightarrow\,\left(A_+A_- + [A_+,A_-]\right)|n> = |n> $$
 
theodoros.mihos said:
##A_+|n> = |n-1> \, , \, A_-|n+1> = |n> ## so
$$ A_+\,A_-\, |n> = |n> \,\Rightarrow\,\left(A_+A_- + [A_+,A_-]\right)|n> = |n> $$

sorry, i don't quite understand. Mind to explain it?
 
## |n> = \Psi_n ## my English is very poor for this theme. ## \frac{d}{dA_+}\left(A_+A_-+1\right) ## is that you need.
 
izzmach said:
I start by defining a function in term of A†, which is f(A†) and solve it using [A , f(A†)] but i get stuck after that. Can someone please explain briefly what i should do in the next step?
You didn't write out the commutation relations in your initial post. I.e., ##~[A, A^\dagger] = \dots ~?##

Start by working out ##[A, (A^\dagger)^2]##, and ##[A, (A^\dagger)^3]## using the Leibniz product rule for commutators. This should help you see the pattern. Then try to prove ##[A, (A^\dagger)^k] = k (A^\dagger)^{k-1}## by induction on ##k##.
 

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