Quantum Mechanics Square Well Potential Problem

Click For Summary
SUMMARY

The discussion centers on solving a quantum mechanics problem involving a one-dimensional square-well potential for a neutron beam incident on a nucleus. The mass of the neutrons is specified as 1.675x10-27 kg, with observed transmission maxima at energies of 1.15 MeV, 23.656 MeV, and 50.254 MeV. The width of the potential is determined to be 10 fm and the depth is calculated to be 10 MeV. The Ramsauer-Townsend Effect is mentioned, highlighting its relevance to the problem, although some participants express uncertainty about its application.

PREREQUISITES
  • Understanding of quantum mechanics principles, specifically square-well potentials.
  • Familiarity with the Ramsauer-Townsend Effect.
  • Proficiency in algebra and solving equations involving energy levels.
  • Knowledge of neutron properties and their interactions with nuclei.
NEXT STEPS
  • Study the derivation of energy levels in one-dimensional square-well potentials.
  • Research the Ramsauer-Townsend Effect and its implications in quantum mechanics.
  • Learn about the mathematical techniques for solving simultaneous equations in physics.
  • Explore neutron scattering experiments and their applications in nuclear physics.
USEFUL FOR

Students and professionals in physics, particularly those focusing on quantum mechanics, nuclear physics, and particle interactions. This discussion is beneficial for anyone seeking to deepen their understanding of square-well potentials and related phenomena.

icantsee99
Messages
4
Reaction score
0

Homework Statement


A beam of neutrons (m=1.675x10-27kg) is incident on a nucleus. Consecutive transmission maxima are observed for beam energies of 1.15, 23.656, and 50.254 MeV. Treating the nucleus as a one-dimensional square-well potential:
(a) What is the width of the potential? (ans. 10 fm)
(b) What is the depth of the potential? (ans. 10 MeV)
The observations are related to the Ramsauer-Townsend Effect

Homework Equations


E = (n2h2)/(8ma2)) -V0

The Attempt at a Solution


I plugged in the mass and energies into the equations, using n=1 for E = 1.15 MeV and n=2 for E = 23.656 MeV. I ended up with

(3.51x1040)a2=-V0
(1.81x1041)a2=-V0

I know that I need another equation, but I don't know what to use. We also never learned the Ramsauer-Townsend Effect in class, so I'm not sure how to apply it. Any input would be appreciated!
 
Last edited by a moderator:
Physics news on Phys.org
icantsee99 said:

The Attempt at a Solution


I plugged in the mass and energies into the equations, using n=1 for E = 1.15 MeV and n=2 for E = 23.656 MeV. I ended up with

(3.51x1040)a2=-V0
(1.81x1041)a2=-V0

I know that I need another equation, but I don't know what to use. We also never learned the Ramsauer-Townsend Effect in class, so I'm not sure how to apply it. Any input would be appreciated!
Check your algebra. The solution to those two equations is a=0, V0=0.
 

Similar threads

Replies
5
Views
3K
Replies
2
Views
4K
Replies
11
Views
3K
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
7K
Replies
16
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K