Quantum Physics - Probabilities

jazznaz
Messages
23
Reaction score
0

Homework Statement



A tritium atom is in the ground state and undergoes beta emission, creating a positively charged Helium ion. Assuming the nuclear change is instantaneous and there are no recoil effects, calculate the probability that the Helium ion will be found in its ground state...

Homework Equations



None

The Attempt at a Solution



I've already shown that the form of the ground state energy eigenfunction is:

\psi (r) = \sqrt{\frac{Z^{3}}{\pi a_{0}^{3}}} e^{-\frac{Zr}{a_{0}}}

where Z is the nuclear charge and a_{0} is the Bohr radius.

I know that the ground state energy for a hydrogenic atom is E_{1}= 13.6 eV.

However, despite looking through my notes and a few books, I can't seem to set up the required probability calculation.

Any help or pointers would be very much appreciated.
 
Last edited:
Physics news on Phys.org
I am not exactly sure how I would do this either, but I think I have an idea behind what the question is trying to say. If someone else can spot my reply as being wrong, tell him so I don't point him in the wrong direction. Let me ask you this: how many electrons does tritium have? How many does the helium ion product have then? What does this tell you about the states of helium? Post again if you are still confused!
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top