Quantum Tunneling Probability Calculation

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SUMMARY

The discussion centers on calculating the quantum tunneling probability for a particle penetrating a potential barrier using the Schrödinger time-independent equation. Key equations include the wave functions before, within, and after the barrier, represented as ψ(x) = e^{ikx} + Re^{-ikx}, ψ(x) = Ae^{imx} + Be^{-imx}, and ψ(x) = Te^{ikx}. The constants k and m are defined as k = ±i√(2mE)/ħ and m = ±i√(2m(U₀-E))/ħ, respectively. The transmission probability is derived from the relation P = |T|²/|I|², with emphasis on solving the resulting system of equations for the unknown variables A, B, R, and T.

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  • Understanding of the Schrödinger time-independent equation
  • Familiarity with quantum mechanics concepts such as wave functions and potential barriers
  • Knowledge of complex numbers and their application in quantum physics
  • Basic skills in solving systems of equations, particularly in the context of physics
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  • Study the derivation of the Schrödinger time-independent equation in detail
  • Learn about boundary conditions in quantum mechanics and their implications
  • Explore methods for solving systems of linear equations, particularly using matrices
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Students studying quantum mechanics, physicists interested in quantum tunneling, and anyone looking to deepen their understanding of wave functions and potential barriers in quantum systems.

nille40
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Hi everyone!
I'm having some problem calculating the probability for a particle to penetrate a barrier (potential well). This is a math assignment in school, and we haven't learned anything about this area, so I may be fumbling in the dark completely.

Anyway, we have the Schrödinger time-independent equation:

\frac{h^2}{2m}\frac{d^2}{dx^2}\psi (x)+U(x)\psi (x) = E \psi (x)

The equation before the barrier is \psi (x) = e^{ikx} + Re^{-ikx} (incoming and reflected wave).
The equation in the barrier is \psi (x) = Ae^{imx} + Be^{-imx}
The equation after the barrier is \psi (x) = Te^{ikx}

If I've calculated right, the constants (k and m) should be:
k = +- i \frac{\sqrt{2mE}}{h}, x < a or x > b
m = +- i \frac{\sqrt{2m(E-U_0)}}{h}

We know that U(x) = 0 when x < a or x > b (outside of the barrier) and U(x) = U_0, a < x < b (inside the barrier).

We have for unknown variables - A,B,R and T. We are supposed to get the probability from |T|^2. We was instructed to derive the functions so that we got 4 function, which should yield an equation system when we attach the functions to each other. So we set:

e^{ika} + Re^{-ika} = Ae^{ima} + Be^{-ima}
Te^{ikb} = Ae^{imb} + Be^{-imb}
ke^{ika} - Rkae^{-ika} = mAe^{ima} - mBe^{-ima}
kTe^{ikb} = imAe^{imb} - mBe^{-imb}

How can I solve this system? Of course, I do not expect you to do this for me, I was just hoping you could help me do it.

Oh, and english isn't my native language, so if the lingo is messed up sometimes - sorry. And I hope the tex stuff works...

Thanks in advance,
Nille
 
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Things are looking pretty good so far. For your function before the barrier, it is usual to include normalization on everything, including the first exponential term (unless you have been told specifically not to).
\psi=Ie^{ikx}+Re^{-ikx}

Other than that, it is a matter of dregding through the equations. It is most likely duable using matrices, or the tedious way. In that case, you will want to solve for A and B in terms of T, then use those relations to solve for I in terms of T. Your transmission probability is then

P=\frac{|T|^2}{|I|^2}

Also, I would choose a different letter for your energy constant inside the barrier, so you don't confuse it with the mass m.
 
Also, I am guessing you are considering the case where 0<E<V. In that case, you might want to check your energy constants. They should probably be

<br /> k=\frac{\sqrt{2mE}}{\hbar}<br />
<br /> \kappa=\frac{\sqrt{2m(U_0-E)}}{\hbar}<br />

Your solution inside the well would then be

<br /> \psi=Ae^{\kappa x}+Be^{-\kappa x}<br />
 
That was fast! Thanks!

Do you have any tips on how to solve the equation system? I tried today, and it seams it is hard to do it...

Thanks!
Nille
 
try to correct and solve this problem

the Schrödinger time-independent equation is written as:
-\frac{h^2}{2m}\frac{d^2}{dx^2}\psi (x)+U(x)\psi (x) = E \psi (x)
Here,I would like to demonstrate the case of 0<E<U.Consider a barrier with a potential of U and width of a.For simplifying,the barrier is from zero to a in x-axis.
The equations at the boundary of the barrier are some different from nille40's.
x=0,\psi (x) &amp; \psi (x)^&#039; are continuous:
1+R=A+B
\frac{ik}{m}(1-R)=A-B
x=a
Ae^{mb}+Be^{-mb}=Te^{ikb}
Ae^{mb}-Be^{-mb}=\frac{ik}{m}Te^{ikb}
Usually,R and T are concerned.To Solve T and R is not so difficult in above equations.
May this can give you some idea.
good luck.
 

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