Quardrature Amplitude Modulation

AI Thread Summary
Quadrature Amplitude Modulation (QAM) involves using a constellation of points to represent multiple signals, where each point corresponds to a unique combination of amplitude and phase. The number of points in a QAM constellation is always a power of two, allowing for efficient multiplexing of signals. Each point in the constellation can represent multiple signals, effectively doubling the number of signals that can be transmitted with each additional point. In the example provided, a channel with a maximum of 20 KHz can accommodate 5 ADPCM signals, leading to the conclusion that a minimum of 3 points (or 8 total combinations) is necessary for multiplexing. This indicates that 8 points can indeed represent up to 256 different signals, demonstrating the efficiency of QAM in digital data transmission.
DrKareem
Messages
101
Reaction score
1
Quardrature Amplitude Modulation.

I know the basic techniques, like when you have 1 point and only two signals are to be multiplexed. But the constellations got me a bit confused. My text-book doesn't explain it thoroughly, and there isn't much deep information about it on the internet.

"The number of "dots" in the constellation is given as a number before the QAM, and is always an integer power of two -- from 2^1 (2QAM) to 2^12 (4096QAM)."

This is from wikipedia site. I'm just wondering, each point adds two signals? or multiply the number of signals mulitplexed by two??


This is an example exercise:

An analog passband channel can pass a maximum of 20 KHz. If the channel is used for transmission of digital data, what is the minimum number of points in a QAM constellation if 5 ADPCM signals are to be multiplexed in an the analog channel?

In both cases of my interpretation, the answer would be 3 points, no??
 
Engineering news on Phys.org
erm, that would be 2^3=8 points.

8 points have the ability to multiplex 16 signals or 2^8= 256??
 
Hi all, I have a question. So from the derivation of the Isentropic process relationship PV^gamma = constant, there is a step dW = PdV, which can only be said for quasi-equilibrium (or reversible) processes. As such I believe PV^gamma = constant (and the family of equations) should not be applicable to just adiabatic processes? Ie, it should be applicable only for adiabatic + reversible = isentropic processes? However, I've seen couple of online notes/books, and...
I have an engine that uses a dry sump oiling system. The oil collection pan has three AN fittings to use for scavenging. Two of the fittings are approximately on the same level, the third is about 1/2 to 3/4 inch higher than the other two. The system ran for years with no problem using a three stage pump (one pressure and two scavenge stages). The two scavenge stages were connected at times to any two of the three AN fittings on the tank. Recently I tried an upgrade to a four stage pump...
Back
Top