Question about centripetal motion problem

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    Centripetal Motion
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To find the angle theta for a biker on a frictionless, circular track, the centripetal acceleration must be balanced with the forces acting on the biker. The relevant forces are gravity and the normal force, which need to be resolved into horizontal and vertical components. The horizontal component must equal the centripetal force, while the vertical component must balance the weight of the biker. Using the relationship tan(theta) = Vy/Vx will help in determining the angle. Properly resolving these forces will lead to the correct calculation of theta.
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Hey I am confused about how to find theta in this problem:

A biker going 20 m/s on a frictionless, circular track of radius 12m banked at an angle of theta degrees

I started by just finding the accel... v^2/r = 400/12 = 33.333

the mass does not matter because it cancels out so...

then I just don't know what to do

any info helps
thanks
 
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i think it has to do with seperating the Vx and Vy and get tan(theta)= Vy/Vx

the Vx and Vy are maybe the centip accel and grav?

idk

thanks
 
frostyman202 said:
i think it has to do with seperating the Vx and Vy and get tan(theta)= Vy/Vx

the Vx and Vy are maybe the centip accel and grav?

idk

thanks
You have the right idea. The only forces acting are gravity and the normal force. Their vector sum has to be horizontal and equal to the centripetal force. Resolve these two forces into horizontal and vertical components as you suggest, and demand that the components lead to the correct sum.
 
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