Question about Delocalisation of Carboxylic Acid and Acctactiveness to Proton

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Deporotonation of carboxylic acids results in the formation of RCOO-, which leads to charge delocalization across the two oxygen atoms. This delocalization stabilizes the anion, making it less reactive and thus enhancing the acidity of the carboxylic acid. Although the negatively charged anion does have an attraction to protons due to its charge, the delocalization means that the attraction is spread out rather than concentrated at a single point. Consequently, this reduces the likelihood of a proton reattaching to the anion, as the proton cannot easily find a specific site for attachment within the delocalized structure.
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So I understand that when you deporotonate a carboxylic acid, you get a RCOO-. This causes a delocalisation in the two oxygen atoms. I read somewhere that because of this delocalisation, it makes it less attractive to Hydrogen ions (protons). This makes the carboxylic acid more stable and thus, a stronger acid.

My question is why the hydrogen ion is less likely to reattach. If protons are positively charged, won't there be some kind of attraction to the negatively charged anion of carboxylic acid?

Thank you.
 
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You sort of answered it yourself. Think about charge delocalization. It stabilizes the anion and that stabilization makes it less reactive than it would be as a full, singular anion.

The delocalization makes both of the oxygen atoms have a partial negative charge, as opposed to only one of them having a full negative, which would be more reactive.
 
You can think about it this way - delocalized charge does attract the proton, but it doesn't attract it to a single place in the COO- group, so it can "touch" the group in any place, not necessarily in the place it can be attached. Very hand-wavy argument, but may help.
 
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