1. Nov 4, 2007

### galuda

1. The problem statement, all variables and given/known data
Consider a steel ball floating on the surface of mercury in a half-filled container. What happens when the rest of the container is filled with water?

3. The attempt at a solution

Wouldn't the ball sink a little farther into the mercury with the added weight of the water on top of the ball? Or would it just stay where it's at? The mercury is obviously going to stay on bottom, and the steel ball is going to float in the water.

2. Nov 4, 2007

### G01

You are correct. The steel ball should sink a little bit farther into the mercury due to the pressure from the water which will be above it.

3. Nov 4, 2007

### galuda

Well apparently the answer was the ball remains partially submerged in mercury but not as deeply as before. I'm not sure I understand why that is, but in case anyone else is wondering, that's the way it is heh.

4. Nov 4, 2007

### G01

Hmm. Maybe it has to do with the buoyancy of the ball. The buoyant force of the water on the ball may cancel with some of the weight, thus causing less submergence in the mercury. Maybe something like this is the case? I don't see how this can be the case is the ball is on top of the mercury and no water is beneath the ball though...

I won't say anything for sure, since I am not sure if this is the case.

5. Nov 4, 2007

### galuda

Yeah, i don't get it either.