Question About Diffraction Orders

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In a double slit system with normally incident light, the number of visible maxima can be calculated using the equation m = d/λ, where d is the slit separation and λ is the wavelength. The value of m indicates the maximum order of diffraction, with a central maximum at m = 0 and additional maxima at both positive and negative values of m. If m is calculated as 8.4, it implies there are 8 visible maxima on one side and 8 on the other, totaling 17 maxima. The intensity distribution is also affected by single slit diffraction, which creates an envelope modulating the intensity of the double slit pattern. Understanding both the double and single slit contributions is essential for accurately determining the total number of maxima.
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Homework Statement


Light is normally incident on a double slit system. I'm asked to calculate the number of "orders(maxima)" visible on a screen placed in front of the slits. The light wavelength and slit separation are given. I understand that I can calculate the "order" from m=d/λ but does this number tell me the total maxima? Or am I to understand that there is a central maximum at m= 0 and then maxima at every ±m? For instance I got m=8.4; Does that mean I have 17 visible maxima or 8?

Thanks!

Homework Equations


dsinθ=mλ

The Attempt at a Solution


I have calculated m but I don't quite understand it's meaning.
 
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There are two things that need to be considered here, the grating equation which you quote gives the angular distribution of the maxima from a single slit. Since you have a pair of slits, there is more going on here. The diffraction from a single slit gives an intensity \approx sinc^2() envelop, the addition of the second slit modulated the intensity within this envelop.

http://web.mit.edu/viz/EM/visualizations/coursenotes/modules/guide14.pdf
 
Dr Transport said:
There are two things that need to be considered here, the grating equation which you quote gives the angular distribution of the maxima from a single slit. Since you have a pair of slits, there is more going on here. The diffraction from a single slit gives an intensity \approx sinc^2() envelop, the addition of the second slit modulated the intensity within this envelop.

http://web.mit.edu/viz/EM/visualizations/coursenotes/modules/guide14.pdf
Okay, thanks for the input, I'm going off of Halliday and Resnick Ch 36.7. He says that the d is the spacing between the slits and I assume that if it's far enough away, dsinϑ=mλ will be sufficient to determine maxima for a double slit setup - I believe that the single slit analogue to this equation, asinϑ=mλ, where a is the slit width, gives orders m which are minima.
 
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