Question about momentum involving shooting a hockey puck

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To determine the speed a hockey player must shoot a puck to push a goalie back five feet, one must consider the coefficient of friction between the ice and the goalie's skates, using the work-energy principle. The total work needed can be calculated with the formula W = Fd, where F is the force and d is the distance. Additionally, the kinetic energy equation K = 1/2mv^2 can help find the necessary velocity of the puck. The impact of the puck will also create a torque around the goalie's center of mass, which must be factored into the calculations. Overall, this analysis combines principles of physics to explore the dynamics of the scenario.
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This is not homework, just a curious question.

What would need to be figured out, to determine how fast a hockey player would have to shoot the puck at a goalie, for the goalie to be forced backwards about 5 feet. The idea was being floated about if a player could shoot a puck so fast that the puck and the goalie would go into the net effectivly being a goal.
 
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Interesting question. I imagine that you are familiar with basic physics formulas?

Here are some ideas for starters:
1. There is a small coefficient of friction between the ice and the goalie's skates. You could assume that the total energy needed is W = Fd = (uN)d = (umg)d.
2. You could relate this to the kinetic energy equation, K = 1/2mv^2, to determine the needed velocity v. You may be disappointed with the result using just the ideas from 1 and 2, since you don't see these results to be true.
3. When the puck impacts with the goalie, this will produce a torque about the goalie's center of mass.

Another idea is to compute the required torque necessary to overcome the friction of the ice/skates and knock the goalie flat on his back and go from there.
 
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