Question about Smooth Interpolation

Click For Summary

Homework Help Overview

The discussion revolves around finding a C^∞ (C infinity) function that is positive on the interval (-1, 1) and zero elsewhere. Participants are exploring the properties and construction of such functions within the context of smooth analysis.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss indirect and direct approaches to constructing the desired function, questioning what obstacles exist in ensuring all derivatives match at the endpoints. One participant proposes a specific function and discusses its properties, while another suggests using a known smooth function as a building block.

Discussion Status

The discussion is active, with participants sharing their thoughts on potential functions and their smoothness properties. There is a sense of exploration regarding the construction of the function, with some guidance provided on the requirements for derivatives at the boundaries.

Contextual Notes

Participants are working under the constraints of needing a function that is not only smooth but also meets specific criteria regarding positivity and behavior at the endpoints of the interval.

chy1013m1
Messages
14
Reaction score
0
any thoughts to this question?
Give an example of a C^oo (C infinity) function f : R->R which is positive on the interval (-1, 1) and 0 elsewhere
 
Physics news on Phys.org
For an indirect approach, you could try constructing one as a limit.


For a more direct approach, figure out what the obstacle is.

You know smooth functions that are zero outside of (-1, 1), and you know smooth functions that are positive inside (-1, 1).

So, what's the problem? You need all of the derivatives to match up. In other words, for your function positive inside of (-1, 1), you need all of its derivatives to be zero at 1 and at -1.

So that's your problem: you need to find a function (other than the zero function) whose derivatives are all zero at some point.
 
just to check if i am on the right track..
let f(x ) = { e ^ (1 / (x ^ 2 - 1)) if -1 < x < 1
0 otherwise
then it is easy to show that
lim f( x) = 0 (split into 2 cases)
x->1 or -1

it is also true that
lim (f(x + h) - f(x)) / h = 0 for x = 1, -1 (show with limit proof)
h->0
then f is C1so then induction on f being Ck, show it is C(k+1)..(if i did it correctly, it should work out..)
then by induction, f is Cinf.
 
Hrm. I find it very plausible that function will work. Incidentally, I was thinking of using the function

[tex] g(x) := \begin{cases}<br /> 0 & x \leq 0 \\<br /> e^{-1/x^2} & x > 0[/tex]

as a building block, since we already know it's smooth. Actually, I think you can build your function out of this, so I'm even more convinced.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 11 ·
Replies
11
Views
5K
  • · Replies 20 ·
Replies
20
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
1
Views
1K
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K