Hi surprise! The marble analogy is a poorly formulated one that leads to misconceptions about what it means for gravitation to be modeled by space-time curvature. GR tells us that test particles in free fall (such as, to a good approximation, the Earth free falling due to the Sun) follow the 'geodesics' of the curved space-time. The geodesics of the curved geometry are, loosely put, the "straightest possible lines" one can have on that geometry. For example, on a 2 dimensional sphere, the geodesics are the great circles (and, in a similar spirit, the geodesics of the space-time around the Sun are to a good approximation those of the Schwarzschild space-time:
http://en.wikipedia.org/wiki/Schwarzschild_metric). The trajectories of test particles free falling in the Sun's vicinity (e.g. the Earth) will follow paths in space-time given by the geodesics of this metric (after supplying initial conditions of course). See here for more:
http://en.wikipedia.org/wiki/Schwarzschild_geodesics
The diagrams which try to model space-time curvature as "dents" in space-time are not accurate because we are actually talking about curvature in 4 dimensions which is extremely difficult to picture so one must settle for so-called 'embedding diagrams'.