Question About the Escape Velocity from Different Mass Planets

AI Thread Summary
Escape velocity is influenced by both the mass and radius of a planet, with the formula V = sqrt((2*G*M)/(R)) indicating that mass (M) is derived from volume multiplied by density. A larger planet does not necessarily have a greater density; if two planets have the same density, a larger radius results in a higher escape velocity. The discussion emphasizes that without specific density values, conclusions about relative densities between planets of different sizes cannot be definitively drawn. Additionally, if a smaller planet has a higher escape velocity than a larger one, it indicates that the smaller planet is denser. Understanding the relationship between size, mass, and density is crucial in analyzing escape velocity.
lify34
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Hi!

I have a question about escape velocity. If a planet is bigger and have a greater escape velocity than another planet. Do this effect the density of the bigger planet in any way? Or do we have to know the mass of the bigger planet to know if the density is larger or lower for this planet?
 
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Do you know an equation for the escape velocity? How are the terms in that equation related to the density?
 
mjc123 said:
Do you know an equation for the escape velocity? How are the terms in that equation related to the density?
V= sqrt ((2*G*M)/(R))

And M is volume * density. Then the density have to be lager, for the bigger planet with a greater escape velocity?
 
How does M vary with R? Put this into the equation, and see how V varies with R for constant density.
 
mjc123 said:
How does M vary with R? Put this into the equation, and see how V varies with R for constant density.

I do not really understand ,as we do not know if they have the same density
 
Assume they do, and see what you get. Compare your result with the hypothesis that the bigger planet must have greater density.
 
lify34 said:
I do not really understand ,as we do not know if they have the same density
Mass equals density x volume.
if we assume a spherical volume, volume = 4 pi R3/3
Thus M= 4 pi d R3/3
where d is the density.
Sub this for M in the escape velocity equation and see what you get.
 
I can see when I have the same density and only change radius R to a larger value, I get a larger value for escape velocity. Maybe it is hard to draw a conclusions from this as we do not know if the density is the same...
 
lify34 said:
I can see when I have the same density and only change radius R to a larger value, I get a larger value for escape velocity. Maybe it is hard to draw a conclusions from this as we do not know if the density is the same...
You can look up the radii, masses and densities of the planets in the Solar system, and you can calculate their escape velocities.
 
  • #10
I think what he is asking is the other way around.
I think he's really asking if a bigger/more massive planet tends to be denser.
I think the escape velocity aspect is an inadvertent red herring.
 
  • #11
DaveC426913 said:
I think what he is asking is the other way around.
I think he's really asking if a bigger/more massive planet tends to be denser.
I think the escape velocity aspect is an inadvertent red herring.
I mean in general. If a planet have a slightly faster escape velocity and is bigger than another planet. What can we say about the density of this bigger planet with a faster escape velocity? Is the density for this planet larger or lower compared to the planet that is smaller and have a less escape velocity?
 
  • #12
lify34 said:
What can we say about the density of this bigger planet with a faster escape velocity?
Not a lot if you don't suggest numbers. It could be more or less dense, or the same density.

Have you done the maths that has been suggested here? If so, post your formula relating density, size and escape velocity. Note that you can use LaTeX for maths - e.g. $$F=\frac{GMm}{r^2}$$See https://www.physicsforums.com/help/latexhelp/
 
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  • #13
That's what I thought, I need more information to be able to draw a conclusion.
upload_2019-2-9_10-0-53.png

V is the escape velocity, g universal gravitational constant, d density and R the radius.

I
 

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  • #14
lify34 said:
That's what I thought, I need more information to be able to draw a conclusion.
View attachment 238512
V is the escape velocity, g universal gravitational constant, d density and R the radius.

I

Your question is a bit like asking:

If person A is bigger and heavier than person B, then what can we say about their relative densities? And, as @Ibix points out, not a lot unless you put some numbers in.

Escape velocity depends on both density and size.

If, however, you have a smaller planet (A) with a greater escape velocity than a bigger planet (B), then you know that A is denser than B.
 
  • #15
Lify, remember that size, mass, and density are 3 different things.
If you have a 1'x'1' cube of styrofoam vs a 1'x1' cube of lead, the size is the same, but the mass and density are much more for the lead. Understanding that will answer your question indefinitely
 
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  • #16
Concrete examples :
Earth:
mass: 5.97e24 kg, density: 5.52 g/c3, escape velocity: 11.19 km/sec

Jupiter:
mass 1.9e27 kg, density: 1.33 g/c3, escape velocity: 59.5 km/sec
 
  • #17
lify34 said:
V= sqrt ((2*G*M)/(R))

And M is volume * density. Then the density have to be lager, for the bigger planet with a greater escape velocity?
No. If the average densities are the same, the escape velocity is directly proportional to the radius.

The volume of a sphere is given by ##\ \text{Volume} = \dfrac 4 3 \pi R^3 \,, \; ## so the mass, M, of a spherical planet of average density, ρ, is:
## M = \dfrac 4 3 \pi R^3 \,\rho ##​
Plug this into the expression for escape velocity, ##v,## to get ##\ v=\sqrt{2G \dfrac {4 \pi R^3}{3R} \,\rho}~, \; ## which simplifies to

##\ v=\sqrt{2G \dfrac {4 \pi }{3} \,} \; \sqrt \rho ~R \ \ . ##​
.
Look at the ratio of escape velocities for planets 1 and 2.

## \dfrac {v_2}{v_1} = \sqrt {\dfrac {\rho_2}{\rho_1} } \cdot \dfrac {R_2}{R_1} ##
.
 
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