Question about the Majorana mass term

phypar
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The Majorana mass term is expressed from a single Weyl spinor. But I am a little confused by the expression. For example, see Eq. (2) in http://arxiv.org/pdf/hep-ph/0410370v2.pdf

\mathcal{L}=\frac{1}{2}m(\chi^T\epsilon \chi+h.c.)

Here \chi is the Weyl spinor and \epsilon = i\sigma^2 is the antisymmetric tensor.

But when I do a simple calculation:
\chi^T\epsilon \chi =(\chi^T\epsilon \chi)^T = \chi^T(-\epsilon) \chi

Here I used \epsilon^T = -\epsilon

therefore \chi^T\epsilon \chi =0

So can anyone tell me what is wrong here? What is missing here? Thanks a lot
 
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you will get an extra minus sign while taking the hemitian conjugate.It is special with σ2.try with a two component spinor of (a b) form explicitly.
 
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:confused: I don't see any σ2 in the expression he's given.

It's just χTεχ = χ1χ2 - χ2χ1 ≡ 0.
 
actually that does not vanish.
 
Thanks for all the replies. I found the mistake in my calculation. \chi_1 and \chi_2 are Grassman variables, thus satisfy the anti-commutation relation, which means \chi_1\chi_2-\chi_2\chi_1 \neq 0
 
In that case, I'm interested in your solution to Exercise 1.4, which says it is zero. :confused:
 
Bill_K said:
In that case, I'm interested in your solution to Exercise 1.4, which says it is zero. :confused:

Because of the Grassmann statistics, 2\chi_1^a\chi_2^b=\epsilon^{\alpha\beta}\chi^a_\alpha\chi_\beta^b is symmetric in a,b.
 
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A simple calculation yields x12,x22 type term,which are zero.
 
andrien said:
A simple calculation yields x12,x22 type term,which are zero.

That term cannot appear in the expression in exercise 1.4. What appears in the expression is an \epsilon_{ab} for the internal indices: there's no 22-component!
 
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