hi guys, how are you all,,
my friend had a quiz and he told me about this question :
container has a square base and the volume of it V= 1000 , find the minimum area of the surface that the container can have ...
A=x^2 , V=x^2 * h
The Attempt at a Solution
i started by saying: 1000=x^2 * h then i can get h =1000/x^2 and A=x^2 then i differentiate 0=2x*h+x^2*h` ... i get at the end (2000/x)-(2000/x)=0 and this doesn't make any sense ,,i tried another way ,, i assumed it should be a cube for the minimum area so i get 6x^2=1000 then i get (x=13) is the answer right?? ,, is the question even right ?? anyone knows how it should be at least ??