Question about the resistor value

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    Resistor Value
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The ideal resistor value for a 3V laser module at 45mA with a 3.3V power supply is calculated as 6.6 ohms, but this setup poses risks if the supply voltage fluctuates. A slight increase in voltage can significantly raise the current, potentially damaging the laser diode. It's recommended to use a constant current source for safety and to avoid exceeding the diode's ratings. Starting with a variable voltage and a fixed resistor in series allows for gradual adjustments until the laser activates, indicated by a noticeable change in light output. For visible lasers, this change is apparent, while for infrared lasers, determining optimal current levels may be more challenging.
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Hello Forum ,
I would like to ask you about the resistor value ideal for a laser module 3V @45mA and the power supply is 3.3V , R= (3.3-3)/45= 6.6 ohm ? it sounds a little strange to me.
Have a nice day and thank you in advance.
 
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yes, that's one of the reasons why you need supply power to a laser diode using a constant current source.
 
It seems risky to have the power supply voltage so close to the laser voltage, though, unless you are sure it isn't going to change.

For example, if the voltage went up to 3.6 Volts, the current would go up to 90 mA. That is double the current for a 9% increase in voltage.

I read up on this a little and it seems you should start with a variable voltage and a fixed resistor in series and gradually increase the supply voltage until the laser starts "lasering".
No idea what that means but I guess it is an obvious change in the light output.
The article I read suggested a 0 to 10 volt supply and a 100 ohm resistor in series, but with a current meter in circuit to see that you don't exceed the laser diode ratings.

If it is a visible laser, you should see a change in behaviour, but if it is infra red, I don't know how you would tell where the best current was.
 
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