Question about the sun and the earth

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The sun exerts a force of 4.0 X 10^28 N on the Earth, which travels 9.4 X 10^11 m in its annual orbit. Despite the significant force, the work done by the sun on the Earth over a year is zero due to the nature of centripetal forces being perpendicular to displacement. While the Earth's orbit is slightly elliptical, the total work remains zero over the complete orbit. The key takeaway is that the displacement over one complete orbit is effectively zero, confirming that no work is done. Understanding the relationship between force, displacement, and the angle between them is crucial in this context.
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The sun exerts a force of 4.0 X 10^28 N on the earth, and the Earth travels 9.4 X 10^11 m in its annual orbit around the sun. How much work is done by the sun on the Earth in the course of a year? Explain.
 
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This is a trick question. The one year length shouold tip you off that displacement is zero, but even if it wasn't, the force is always perpendicular to the displacement by definition. This means that a centripetal force of any kind does no work to displace the rotating object.
 
turdferguson said:
This is a trick question. The one year length shouold tip you off that displacement is zero, but even if it wasn't, the force is always perpendicular to the displacement by definition. This means that a centripetal force of any kind does no work to displace the rotating object.
Not quite. The work done is the dot product of force and displacement:

dW = \vec{F}\cdot \vec{ds} = Fds\cos\theta

Unless the orbit is perfectly circular (the Earth orbit is close to circular but is slightly elliptical) the force is not always perpendicular to velocity or displacement of the Earth (hence \cos\theta \ne 0 and dW \ne 0). However, over a period of a full year, as you have correctly pointed out, the total work is 0.

AM
 
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