Question about units for arcsecond

  • Thread starter Thread starter leonne
  • Start date Start date
  • Tags Tags
    Units
AI Thread Summary
To find the diameter of an object in the sky using arcseconds, it's important to understand that the tangent of an angle is a dimensionless quantity, meaning it has no units. When calculating diameter using the formula d=2Dtan(a/2), the angle in degrees can be converted to radians, but the tangent function itself does not carry units. The discussion clarifies that the units of tangent can be expressed as Length/Length, reinforcing that it simplifies to a pure number. Ultimately, the focus is on correctly applying the formula without needing to worry about the units of the angle in the context of the calculation. Understanding this concept is crucial for determining the time it takes for an explosion to reach 1 arcsecond.
leonne
Messages
163
Reaction score
0

Homework Statement


I need to find the diameter of an object in the sky, which i did, but not sure about the arc second.
I convert it into degrees wondering how i would remove the degrees.


Homework Equations


d=2Dtan(a/2)


The Attempt at a Solution


where D is distance a is angular d is diameter and so i got like 7.47e17cm degrees do I just ignore the degrees? or I need to do something else to remove it? need the radus so i can find the time it takes the explosion to reach 1 arc sec
thanks
 
Physics news on Phys.org
The tan of an angle is a pure number without units.
 
yeah just figured it out thanks
 
gneill said:
The tan of an angle is a pure number without units.

Could you also say that the units of tan() are Length/Length = 1?
 
berkeman said:
Could you also say that the units of tan() are Length/Length = 1?

You could. Actually, it can be the ratio of any like sets of units, such as N/N, or (m/s)/(m/s), and so on.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top