AxiomOfChoice
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I'm trying to simplify the expression
<br /> (\hat{r} \times \vec{\nabla}) \times \hat{r},<br />
where \hat{r} is the radial unit vector, using index notation. I think I'm right to write this as:
<br /> ((\hat{r} \times \vec{\nabla}) \times \hat{r})_i = \varepsilon_{ijk}(\varepsilon_{jmn}r_m\partial_n)r_k.<br />
But when I employ the contraction
<br /> \varepsilon_{ijk}\varepsilon_{jmn} = \delta_{im}\delta_{kn} - \delta_{in}\delta_{km}<br />
and simplify, what I wind up with is this:
<br /> r_i \partial_k r_k - r_k\partial_ir_k.<br />
I'm thinking that this first term becomes \hat{r} (\nabla \cdot \hat{r})...is that right? And what about the second term? I'm kind of clueless as to what to do with that.
I might have made other mistakes here, though, so I'd appreciate someone pointing them out. Thanks.
<br /> (\hat{r} \times \vec{\nabla}) \times \hat{r},<br />
where \hat{r} is the radial unit vector, using index notation. I think I'm right to write this as:
<br /> ((\hat{r} \times \vec{\nabla}) \times \hat{r})_i = \varepsilon_{ijk}(\varepsilon_{jmn}r_m\partial_n)r_k.<br />
But when I employ the contraction
<br /> \varepsilon_{ijk}\varepsilon_{jmn} = \delta_{im}\delta_{kn} - \delta_{in}\delta_{km}<br />
and simplify, what I wind up with is this:
<br /> r_i \partial_k r_k - r_k\partial_ir_k.<br />
I'm thinking that this first term becomes \hat{r} (\nabla \cdot \hat{r})...is that right? And what about the second term? I'm kind of clueless as to what to do with that.
I might have made other mistakes here, though, so I'd appreciate someone pointing them out. Thanks.