Question dealing with density and pressure

  • Thread starter Thread starter tophat22
  • Start date Start date
  • Tags Tags
    Density Pressure
AI Thread Summary
The discussion revolves around understanding pressure and force in a dam holding a reservoir with two different densities: sludge and water. For part a, pressure is determined by the weight of the fluid above, and since the densities are constant within their respective sections, integration is not necessary. Part b involves calculating the horizontal force on the dam, which requires considering the varying pressure at different depths. The conversation highlights the importance of recognizing when to use integration based on density variations. Overall, the participants aim to clarify the approach to solving the physics problem effectively.
tophat22
Messages
4
Reaction score
0
I haven't taken physics in a while, and most of this is physics related. My professor's lectures have not helped me understand the material, so I have questions on my homework. I would like to learn how to approach this problem and solve it.


The figure shows a vertical dam holding back a reservoir of depth h. The lower half of the reservoir consists of a sludge whose density is twice that of water, and the upper half of the reservoir's volume consists of pure water.

a. Determine how pressure depends on altitude z in the water and sludge.
b. Let w be the dam's width, and determine the horizontal component of force on the dam.


Thank you in advance.
 

Attachments

  • questionfig.jpg
    questionfig.jpg
    17.8 KB · Views: 404
Physics news on Phys.org
Welcome to PF!

Hi tophat22! Welcome to PF! :smile:
tophat22 said:
The figure shows a vertical dam holding back a reservoir of depth h. The lower half of the reservoir consists of a sludge whose density is twice that of water, and the upper half of the reservoir's volume consists of pure water.

a. Determine how pressure depends on altitude z in the water and sludge.
b. Let w be the dam's width, and determine the horizontal component of force on the dam.

a. The pressure is basically the weight of the fluid above (per area). :smile:

b. Pressure = force per area, so the force on the dam is the integral of pressure times area. :wink:
 
for part a, what am I supposed to do with vector z? will I have to deal with an integral?
 
Hi tophat22! :smile:
tophat22 said:
for part a, what am I supposed to do with vector z? will I have to deal with an integral?

No, you'd only need an integral if the density was varying continuously

but here, it's constant to a certain height, and then a different constant, so you can just multiply instead of integrating. :smile:
 
tiny-tim said:
Hi tophat22! :smile:


No, you'd only need an integral if the density was varying continuously

but here, it's constant to a certain height, and then a different constant, so you can just multiply instead of integrating. :smile:

Since the pressure varies with depth there will be a different force on the dam at different depths. So integration would be needed.

CS
 
tophat22 said:
for part a, what am I supposed to do with vector z? will I have to deal with an integral?
stewartcs said:
Since the pressure varies with depth there will be a different force on the dam at different depths. So integration would be needed.

CS

Hi stewartcs! :smile:

Not for part a. :wink:
 
tiny-tim said:
Hi stewartcs! :smile:

Not for part a. :wink:

Sorry I missed the "part a" there! :blushing: Silly me...I should not post until my morning tea!

CS
 
It's afternoon here in London! :biggrin:

'll soon be proper tea-time

… and time for "Countdown" on telly. :-p
 
Back
Top