Question involving some reasoning.

  • Thread starter Thread starter azatkgz
  • Start date Start date
AI Thread Summary
In the scenario where fifty gangsters shoot each other simultaneously, the key question is determining the minimal number of casualties. The proposed solution involves dividing the gangsters into five groups, with only two gangsters in the center of each group being shot, leading to a total of ten deaths. The reasoning is based on the assumption that gangsters will target the closest individuals, resulting in a pattern of shooting that minimizes fatalities. The solution suggests that strategic positioning can significantly impact the outcome. Overall, the conclusion drawn is that a maximum of ten gangsters can be killed under these conditions.
azatkgz
Messages
182
Reaction score
0

Homework Statement


Fifty gangsters on a field are shooting each other simulteneously.Assume that
i.Gangsters are points on the plane.
ii.Gangsters don't miss,so once he shoots at someone,the target is killed.
iii.Each gangster shoots the one that is closest to him(or any of the closest ones if they are on same distance from him)

What is the minimal number of dead bodies?They shoot each other just once,all fifty at the same moment.Guess the answer and then try to prove it.





The Attempt at a Solution


I divided 50 gansters to 5 groups.In each group only 2 gansters in the center of circle are dying(see picture).With arrows I showed direction of shooting.So my answer is only 10 gansters.
 

Attachments

  • Gansters.jpg
    Gansters.jpg
    14.5 KB · Views: 442
Physics news on Phys.org
I'm no mathematician but it looks good to me.
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
Back
Top