Question involving velocities and distance

[drummerdimitr]

Homework Statement

Two soccer players, Mary and Jane, begin running from nearly the same point. Mary runs in an easterly direction at 4 m/s, while Jane takes off in a direction 60 degrees north of east at 5.4 m/s. (a) How long before they are 25 m apart? (b) What is the velocity of Jane relative to Mary? (c) How far apart are they after 4 s?

Homework Equations

D=v/t
Yf=Yi+(Vy)iT+1/2at^2
Xf=Xi+(Vx)iT

The Attempt at a Solution

T must be the same value in both equations, but I do not know how to convert velocity vectors with a 60 degree separation into distance to solve the problem. I have a test tomorrow and your input would be much appreciated!

 

[tiny-tim]

Welcome to PF!

Hi drummerdimitr! Welcome to PF!

(try using the X² tag just above the Reply box )

Hint: If you can answer (b) first, then (a) should be easy.

 

[drummerdimitr]

Thanks for the quick reply, I found the answer to part c by multiplying the velocities by 4 and finding the length of the third side. I tried doing vector addition and ended up with a relative velocity of 8.17 m/s at 34.9 degrees north degrees, but unfortunately, it is not the right answer. What am i doing wrong here?

 

[tiny-tim]

(just got up :zzz: …)

I tried doing vector addition and ended up with a relative velocity of 8.17 m/s …

ahh … for relative velocities, try vector subtraction!