Understanding Gaussian Integral: Question on Hinch's Perturbation Theory Book

liyz06
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Homework Statement


I'm reading Hinch's perturbation theory book, and there's a statement in the derivation:
...\int_z^{\infty}\dfrac{d e^{-t^2}}{t^9}<\dfrac{1}{z^9}\int_z^{\infty}d e^{-t^2}...

Why is that true?

Homework Equations


The Attempt at a Solution


Homework Statement


Homework Equations


The Attempt at a Solution

 
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liyz06 said:

Homework Statement


I'm reading Hinch's perturbation theory book, and there's a statement in the derivation:
...\int_z^{\infty}\dfrac{d e^{-t^2}}{t^9}<\dfrac{1}{z^9}\int_z^{\infty}d e^{-t^2}...

Why is that true?


Homework Equations





The Attempt at a Solution


Because 1/t^9 for t in (z,infinity) is less than 1/z^9. Draw a graph.
 
Dick said:
Because 1/t^9 for t in (z,infinity) is less than 1/z^9. Draw a graph.

Thanks, really stupid question
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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