Question on Momentum, Force and Impulse

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Car safety features like crumple zones and rigid steel safety cages are designed to enhance passenger protection during collisions. Crumple zones, located in the engine compartment and boot, absorb impact by collapsing, which extends the time of deceleration. A car with a mass of 900 kg traveling at 10 m/s has a momentum of 9000 kg·m/s before hitting a wall, and the final momentum after the collision is zero. The change in momentum is the same regardless of whether crumple zones are present, but the rate of change differs, resulting in different forces: a higher force without crumple zones and a lower force with them. This illustrates the importance of crumple zones in reducing the force experienced by passengers during an impact.
Chan1993
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Car makers build in many safety features to their cars. Some advertise these features a great deal so that many people will have heard of 'crumple zones' and 'rigid steel safety cage'. Seat belts have also lead to increased safety.

The crumple zone in a car are the engine compartment and the boot. These are designed so that they crumple or collaspe in a serious collison so that the impact is spread over a longer time. The safety cage is a cage of strong steel bars around the passenger space which is hidden in the body of the car.

a) A car of mass 9.00 x 102 kg traveling at 10ms-1 when it skids off the road and into a concrete wall. If the car does not have crumple zones, it is stopped in 0.0500s; if it does have crumple zones, the slowing down process, is 0.900s longer

i) What is the momentum of the car before it hits the wall?
ii) What is the momentum after the collision?
iii) What is the change of momentum?
iv) How big is the force stopping the car if it does not have crumple zones?
v) How big is the force if it does not have crumple zones?
vi) Comment on your answers for (iv) and (v).

  • Momentum: p = mv
  • Ft= mv-mu
  • F=ma
Momentum before= p = 900 x 10 = 9000kgms

sigh that's all I can do...


I think you're also suppose to use \SigmaBefore = \SigmaAfter
 
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I think you should think that since an impulsive force has acted on car,we cannot use Conservation of Momentum.The final momentum is $0$.

Change in momentum is same in both the cases,but 'rate of change of momentum' is different and thus,the forces are different.
 
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