Question on thermal equilibrium?

AI Thread Summary
Pouring water into an overheated automobile engine should be done slowly and with the engine running to prevent thermal shock. Rapid cooling can cause uneven temperature distribution, leading to damage such as cracking due to thermal stress. Keeping the engine running allows for better circulation of coolant, which helps maintain a more uniform temperature throughout the engine components. Adding water gradually ensures that it mixes properly and minimizes the risk of introducing cold water to overheated areas. This approach ultimately protects the engine from potential damage caused by sudden temperature changes.
Shindo
Messages
12
Reaction score
0
So I'm not too sure about the answer to this question: explain why it is advisable to add water to an overheated automobile engine only slowly, and only with the engine running?

So if something is overheating, it makes sense to want to cool it. Since the water's temperature is less than that of the engine, pouring it on will lower the temperature of the engine. But what about thermal equilibrium, and engines in particular, makes it risky to pour in water quickly? Will too much water mean that the liquid will hit the engine without being boiled, thus damaging the engine? And what about an engine running makes it advisable? Is it because it keeps its overheating temperature constant?
 
Physics news on Phys.org
Shindo said:
what about thermal equilibrium, and engines in particular, makes it risky to pour in water quickly?
The way the forum works, is that you have to commit to an answer/approach. Pick something, and defend it.
Shindo said:
thus damaging the engine?
You're fishing. It's close, so try developing the idea a bit. "Damage how?"
Shindo said:
keeps its overheating temperature constant?
More fishing. Develop the idea.
 
Bystander said:
The way the forum works, is that you have to commit to an answer/approach. .
Yeah, this was a difficult question to think about, because I'm not sure if an understanding of engines was needed or not. If I had to pick an answer it would be that the water needs to be boiled first, and too much water means only some of the water is boiled whereas the rest of the water can damage the engine. However, since I'm ignorant when it comes to car engines (thermal equilibrium too) I'm not sure if THIS is the particular reason why it's wise to pour the water slowly. I know that this forum doesn't concern itself with automobiles, so I'm guessing that the question itself shouldn't need an understanding. Without it being boiled, the liquid may hit other parts of the engine NOT overheating, and thus shrink the parts of the engine. The shrinking will cause a damage to the engine.
 
Shindo said:
thus shrink the parts of the engine. The shrinking will cause a damage to the engine.
Bingo. Just like baking marbles on a cookie sheet and dropping them into water to make fractured marbles for interior decoration --- or, you're too young, and Ralph Nader forbade your mother from doing that? "Temperature shock." Great.

Now, why keep the engine running (which keeps the water pump running) as you add water slowly?
 
Bystander said:
Now, why keep the engine running (which keeps the water pump running) as you add water slowly?

Well, if the engine is off the engine will slowly but surely cool down. But maybe not evenly. Adding water when it's at its hot state gives a more even distribution of equilibrium, so the engine won't break off.
 
Shindo said:
a more even distribution of
Coolant is circulated through the engine by the "water pump" (little water and a lot of ethylene glycol), and lowering the coolant's temperature by gradual addition of water prevents large temperature differences being produced in the block or heads that might crack those pieces. Almost guaranteed to happen if you turn cold water on a dry hot engine.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Back
Top