Question regarding energy from chemicals (M.C.Q)

  • Thread starter Thread starter hamxa7
  • Start date Start date
  • Tags Tags
    Chemicals Energy
AI Thread Summary
When 100 cm3 of 1 mol dm3 sodium hydroxide reacts with 100 cm3 of 1 mol dm3 hydrochloric acid, the temperature rise T1 is observed. In contrast, when the volumes are halved to 50 cm3 each, the temperature rise T2 is recorded. The total energy released during the reaction is proportional to the number of moles, so reducing the volume also reduces the energy released. Thus, T2 is half the value of T1, confirming that the correct answer is C. The calculations demonstrate that the energy liberated per mass of solution is consistent across both experiments, reinforcing the relationship between volume and energy release.
hamxa7
Messages
4
Reaction score
0
Q. A volume of 100 cm3 of 1 mol dm3 sodium hydroxide solution was added to 100 cm3 of 1 mol dm3 hydrochloric acid.The maximum rise in temperature recorded was T1.The experiment was repeated with 50cm3 of each solution and the rise in temperature this time was T2. It is found That


A) T1 Is Equal To T2
B) T1 Is Half The value Of T2
C) T2 is half the value of T1
D) T2 Is a quarter the value of T1.


I think the Ans Should Be C as the volume is decreased...
What do you think as the answer given is A...

reply quickly... :-)
 
Physics news on Phys.org
The volume is decreased, but the total energy of reaction is decreased in proportion. Remember energies of reaction are per mole, so if you cut the number of moles of reactant in half, the total energy liberated is also cut in half.
 
can you explain it in further detail...
examples would be appreciated..
 
Assume 1 mole of NaOH reacting with 1 mole HCl liberates energy Q. Calculate how much energy is liberated in both cases (in terms of Q). Calculate masses of solution in both cases. Calculate ratio of energy liberated to final mass of the solution for each case (again in terms of Q, assume density of 1g/mL). What did you get?
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top