Question regarding onto function

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Hi.
I know what an onto function is.
I found this statement on a problem:
f(x) is a function from a set Z onto itself.

Now does this mean that f(x) is an "onto" function or is the word used just like that(like an english word)?
What if it was:
f(x) is a function from a set Z into itself.
Would it mean its an into function?

Thank You.
I hope someone clarifies this out for me.
 
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sachin123 said:
Hi.
I know what an onto function is.
I found this statement on a problem:
f(x) is a function from a set Z onto itself.

Now does this mean that f(x) is an "onto" function or is the word used just like that(like an english word)?
It indeed means f(x) is a surjective function.
What if it was:
f(x) is a function from a set Z into itself.
Would it mean its an into function?
What's an into function?
Thank You.
I hope someone clarifies this out for me.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

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