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B Question regarding waves

  1. Jun 20, 2016 #1
    Every moving object has a wave associated with it. If a electron is moving with a speed v we can use ##\lambda = \frac{h}{mv}## to calculate the wavelength of the associated wave and thus the frequency can be calculated. This frequency denotes some kind of oscillation. So what is oscillating here?
  2. jcsd
  3. Jun 21, 2016 #2


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    The "electron field" is oscillating. I am not talking about the electrostatic field produced by the electron due to its charge or the electromagnetic field due to the movement of electron, but about the quantum fermionic field of which electron is a quantum of energy. According to quantum field theory every particle has an associated field of which the particle is a quanta of energy of that field.
  4. Jul 3, 2016 #3
    Are you talking about excitation of field?
    i.e. If the "Electron Field" is excited at a particular position an electron is created?
    Does the field actually moves or just the magnitude changes? What is the unit of its magnitude?
    If electron is stationary the field will not oscillate and if it is given some kinetic energy the field oscillates.Where this oscillation occurs?How it occurs?
  5. Jul 3, 2016 #4


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    Sorry I am not particularly good with quantum field theory. Maybe my first post was not correct to "mix" the deBroglie wave with a wave in the fermionic field.
  6. Jul 4, 2016 #5
    Well,I agree with you. I think you are right to some extent, until someone contradicts us.
    Thanks for your help.
    Waiting for more help from someone.
  7. Jul 5, 2016 #6


    Staff: Mentor

    That's false.

    Its a left over from the outdated ideas of early quantum theory that was consigned to the dustbin of history during 1925/1926, but most certainly by 1926 when Dirac came up with his transformation theory that pretty much goes by the name of QM today:

    Here is a much much better way of looking at QM:

    Standard QM is an approximation to Quantum Field theory which in a certain, loose sense, is said to be an infinite number of oscillators:

    But as explained above only in a loose and imprecise sense.

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