Questionable resistance pictures included

AI Thread Summary
To determine if battery voltage drops at a 6A current, Circuit a is preferred due to its lower resistance. The current flowing through the headlight in both circuits is calculated to be 2.4e-4 A when the voltmeter is connected. Before the voltmeter is added, the headlight operates at 6A. The resistance of the headlight is significantly lower than that of the voltmeter, which is designed to minimize current draw. Choosing the correct circuit is crucial for accurate voltage measurement without affecting the circuit's performance.
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Homework Statement


You would like to check if the battery voltage drops while it is supplying a current of 6A. You use a voltmeter designed to measure voltages up to 20V and having a resistance of 50,000 Ohms. Which of the two circuits below should be used?
a.) How much current (in A) would flow through the headlight for Circuit a?
b). How much current (in A) would flow through the headlight for Circuit b?

OA-Voltmeter.jpg




Homework Equations


delta(V) = IR


The Attempt at a Solution



Circuit a should be used because it has the least resistance.

a.) I = 12/50000 = 2.4e-4
b.) I = 12/50000 = 2.4e-4
 
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Before putting the voltmeter into the circuit the current passing in the headlight is 6 amps.
What is the resistance of the headlight?
How does that compare to the resistance of the voltmeter?

The purpose of a voltmeter is to measure a voltage while actually disturbing that voltage as little as possible. Voltmeters are designed to draw as little current as possible.

Now consider which diagram is appropriate.
 
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