Questions relating to UMVUE/transformations

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Homework Help Overview

The discussion revolves around finding the Uniformly Minimum Variance Unbiased Estimator (UMVUE) for parameters of the Rayleigh and Weibull distributions. Participants explore the transformations of random variables and their implications for estimating parameters.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the transformation of variables and the resulting distributions, questioning the validity of applying similar methods to different distributions. There is also inquiry into the definitions of UMVUE and CRLB, as well as the implications of using complete sufficient statistics.

Discussion Status

Some participants express confusion regarding the similarities in the transformations leading to the same distribution type, while others seek clarification on the definitions and properties of UMVUE and CRLB. There is an ongoing exploration of whether the same methodology can be applied across different distributions.

Contextual Notes

Participants note that the problems are assigned consecutively, which may influence their understanding of the relationships between the distributions and the transformations. There is also mention of the need to evaluate the information contained in the data sets for the respective distributions.

abeliando
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So one of my assignments was to find a UMVUE of a Rayleigh distribution, that is the pdf
f(x;θ)=2θ-1x*exp(-x2/θ).
the suggestion was to use U=Ʃx2i. When I do this, I do a transformation with Ui=X2i and find that Ui has an exponential distribution, and the U=ƩUi follows a gamma(n,θ), so then n-1E(U)=θ, so then U-bar is the UMVUE of θ. I think this is correct.

So then I am asked to see if it attains the CRLB, and I use the fact that U is Gam(n,θ) to show that yes indeed, it does reach the CRLB. All is well and good. Also, I'm asked to find the estimators of θ2 and θ-1, and find their variances. I did this, and it all relied on the fact that it was gamma distributed.

On the next problem, I'm given that X follows a Weibull, that is, has the pdf
f(x;θ)=α-1βxβ-1*exp(-xβ/α), where β (>0) is known, and it suggests starting off with U=ƩXβi. So when I make this transformation, I find the same thing, that Ui is exponential, so U=ƩXβi is distributed Gam(n,α).

So here's why I'm confused. In both cases, I started with a pdf, transformed it to a different variable, but otherwise, finding the estimators and their variances aren't based on their original distribution, but the transformed distribution, which is the same. So I'd imagine that I just cut and paste my original work. It can't be that easy, right? What am I missing? The problems in the text are assigned right after each other, so... I'm assuming I'm wrong. Any help?
 
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What's a UMVUE? What's CRLB? (I *think* I know what the last one means, but how can I be sure?)
 
UMVUE = Uniformly Minimum Variance Unbiased Estimator, CRLB = Cramer Rao Lower Bound (defined as the first derivative of a function of a parameter squared, over the information contained by the set of data) (τ(θ)')2/IX

So by Lehmann-Scheffe theorems, if I take a complete sufficient statistic that is unbiased for an parameter, that statistic is the UMVUE. In my cases, the suggested statistics that I started off with are complete sufficient, and then taking the average is still complete sufficient.

CRLB is the function that states what the theoretical minimum variance for an estimator is, and then I just take the variance to see if it actually works
 
Hm, this is a little bit tricky. If I did my work correct, I suppose it does make sense, and rely on the previous distribution. I am confused about the two U's (U_1=ƩX2i and U_2=ƩXβi apparently having the same distribution. And I guess what I' m saying is, is that in the first case, if X follows a Rayleigh distribution, then U_1 follows a Gamma(n,θ) distribution. Also if X follows a Weibull distribution, then U_2 follows a Gamma(n,θ) distribution. So it does depend on the original distribution. Is this correct?

This makes sense. It would also make sense that the work would be same, I guess.

Oh, and the information contained in the set will (should) be different (I haven't evaluated it yet).

I think I figured it out, yes?
 

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