Group Elements a,b,c,d,e: Inverse Operation?

  • Thread starter Thread starter Punkyc7
  • Start date Start date
  • Tags Tags
    Group
Punkyc7
Messages
415
Reaction score
0
Lets say i have elements a,b,c,d,e in some group.


is abcde always = ab(d^-1c^-1)e. My question is and you change elements in the middle of an operation by using the inverse?
 
Physics news on Phys.org
Certainly this is not true. Take your equation and cancel the a, b, and e by multiplying on the appropriate side by the appropriate inverse in each case. You are left with

cd = (d^-1 c^-1)

and the right hand side is equal to (cd)^-1.

Obviously in general, cd does not equal its own inverse, so the equation is false.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top