Quick parametric equation question

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Homework Help Overview

The discussion revolves around finding a parametric representation for the lower half of the ellipsoid defined by the equation 3x² + 5y² + z² = 1. Participants are exploring how to express the variable z in terms of parameters x and y, specifically using u and v as substitutes for x and y.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • One participant attempts to solve for z by rearranging the ellipsoid equation and substituting x and y with u and v. However, they express uncertainty about the correctness of their approach, particularly questioning whether z should be negative for the lower half of the ellipsoid. Another participant suggests using modified spherical coordinates as an alternative method, raising questions about the necessity of using x and y directly as parameters.

Discussion Status

The discussion is active, with participants sharing their attempts and questioning the assumptions made in their approaches. Some guidance has been offered regarding the use of spherical coordinates, but there is no explicit consensus on the best method to proceed.

Contextual Notes

Participants are grappling with the constraints of the problem, including the requirement to represent the lower half of the ellipsoid and the implications of using specific parameterizations. There is also a mention of symmetry in the problem that may influence the choice of parameters.

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Homework Statement




Find a parametric representation for the lower half of the ellipsoid 3x^2 + 5y^2 + z^2 = 1
x=u
y=v

z=??

we need to find what z is


The Attempt at a Solution



i solved the equation for z getting

z= sqrt(1-3x^2-5y^2)

then i plugged the given x=u and y=v into equation
to get
z= sqrt(1-3u^2-5v^2)

but that is wrong?
what should i do instead??
 
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fball558 said:

Homework Statement




Find a parametric representation for the lower half of the ellipsoid 3x^2 + 5y^2 + z^2 = 1
x=u
y=v

z=??

we need to find what z is


The Attempt at a Solution



i solved the equation for z getting

z= sqrt(1-3x^2-5y^2)

then i plugged the given x=u and y=v into equation
to get
z= sqrt(1-3u^2-5v^2)

but that is wrong?
what should i do instead??

shouldn't z be negtive for the lower half?
 
:( yes... i need to learn how to read.
thanks a lot lanedance
that is right :)
 
Did the problem specifically say that you must use x and y themselves as parameters? There is enough "symmetry" here that I would have use "modified" spherical coordinates:
x= \frac{\sqrt{3}}{3}cos(\theta)sin(\phi)<br /> y= \frac{\sqrt{5}}{5}sin(\theta)sin(\phi)<br /> z= cos(\phi)<br /> with 0\le \theta< 2\pi and \pi/2 \le \phi \le \pi.
 

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