Quick Partial Derivatives question - exp(x+z)

Click For Summary
SUMMARY

The discussion centers on finding the partial derivative of the function f(x, y, z) = exp(x + z) with respect to the variable y. The conclusion reached is that the partial derivative del(f)/del(y) equals 0, as the function does not contain the variable y, thus treating it as a constant. This confirms the fundamental principle that the derivative of a constant is zero.

PREREQUISITES
  • Understanding of partial derivatives in multivariable calculus
  • Familiarity with the exponential function, specifically e^(x + z)
  • Knowledge of basic calculus concepts, including constants and variables
  • Ability to apply differentiation rules to functions of multiple variables
NEXT STEPS
  • Study the concept of partial derivatives in multivariable calculus
  • Learn about the implications of treating variables as constants in differentiation
  • Explore the properties of exponential functions and their derivatives
  • Practice solving partial derivatives with various functions involving multiple variables
USEFUL FOR

Students studying calculus, particularly those focusing on multivariable calculus, as well as educators looking for examples of partial derivatives in action.

maks4
Messages
36
Reaction score
0

Homework Statement


Finding the partial derivative with respect to y, so del(f)/del(y)


Homework Equations


exp(x+z) - that is e^(x+z)


The Attempt at a Solution


I firstly thought this was just e^(x+z) but then i realized, shouldn't it be just 0? Since you're finding the partial derivative with respect to y, and since there's no y variable in there, wouldn't it be 0, ie treating the whole equation as a constant?
 
Physics news on Phys.org
Yes it would.
 
Thank you!
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
9
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
4K
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
4
Views
1K