Quick Projectile Motion Problem

AI Thread Summary
The discussion revolves around solving a projectile motion problem involving a child throwing an apple core from a height of 4.0 meters at a velocity of 5.0 m/s at a 35-degree angle. Key calculations include determining the time of flight, horizontal distance traveled, and the impact velocity. The time before the apple core hits the ground is approximately 1.24 seconds, the horizontal distance from the tree is about 5.09 meters, and the impact velocity is calculated to be 3.78 m/s. Participants emphasize the importance of understanding the relationships between quantities and checking the reasonableness of answers to build confidence in problem-solving. The discussion highlights the value of both algebraic and graphical methods in verifying results.
quicksilver123
Messages
173
Reaction score
0

Homework Statement



A child sitting in a tree throws his apple core from where he is perched (a height of 4.0m) with a velocity of 5.0m/s [35 deg above horizontal] and it hits the ground right next to his friend.

a)how long is it before the apple core hits the ground?
b)how far from the base of the tree will the apple core land?
c)what is the velocity of the apple core on impact?

Homework Equations



suvat
pythag.
quad. form.

The Attempt at a Solution



Given:
Vi=5.0m/s [35 deg above horizontal]
Δdy = 4.0m

a)

Find Δt.

Let [down] and [forward] be positive.

Initial Velocity Components:
Vix = 5m/s (cos35) = 4.095760221m/s
Viy = 5m/s (sin35) = -2.867882182m/s
*Note: I threw the negative on the y-component because it is traveling upwards.

Acceleration Components:
ax = 0m/s/s
ay = 9.8m/s/s

Calculation for part A:
Δdy = ViyΔt +1/2 (ay)Δt2
4.0m = -2.867882182m/s Δt + 4.9m/s/s (Δt2)

In order to isolate the time variable, I rearranged to the form ax2+bx+c=0 and solved via the quadratic formula.
The only real root yielded was x=1.242359580605109

Therefore, Δt = 1.242359580605109 seconds


b)
Find Δdx.

Calculation for part B:
Δdx = VixΔt +1/2 (ax)Δt2
Δdx = 4.095760221m/s (1.242359580605109 seconds) + 0
Δdx = 5.08840695042 m


c)
Find Vf

Components of Vf:
Vfx
Vfx2 = Vix2+2axΔdx
Since ax=0m/s/s, Vfx=Vix
∴ Vfx=5m/s

Vfy
Vfy2 = Viy2+2ayΔdy
Vfy2 = 8.22474821m2/s2 + 78.4m2/s2
Vfy = √86.62474821
Vfy = 9.307241708m/s

Vf = √(Vfx2 +Vfy2
Vf = √14.30724171
Vf = 3.782491469m/s



Answers rounded:

Δt = 1.24 seconds
Δdx = 5.088 m
Vf = 3.78 m/s

I know the sig digits aren't correct but I didn't want to sacrifice accuracy.


Are these answers correct?
 
Last edited:
Physics news on Phys.org
"Viy = 5m/s (sin35) = -2.867882182m/s"

missed a minus sign from in front of the 5 :)

Note: you are being trained to be able to solve problems where nobody knows the answer.
This means you need to figure out how to tell if you've got it right without having to ask someone else. Problems like the one you just did are great for practicing this - for instance,
Does the result you got make sense?
Can you identify the source of your uncertainty with your answers?
Is there another way of doing the problem, eg. graphically, that will help you tell if it's right or not?
 
I'm not really sure how to tell if I got it right.
Obviously there are some cases where a wrong answer will make absolutely no sense (eg. in this case - Δdx = -500m would be blatantly incorrect) but the majority of errors that go uncaught will be more subtle. You seem to have some ideas on this topic, could you share them?
I like your point about finding points of uncertainty in calculations.
Doing the problem graphically, at least in this case (I think), would only help with a visual representation. I guess that one could use calculus to find the point where the projectile reached the maximum height, and then calculate the downward trajectory from there in the context of the problem to get an answer... but that doesn't seem like the most straightforward way to attack something like this.
 
One of the ways to gain confidence in your answer is to do the algebra first - then add the numbers in.
That way you keep track of the relationships between the different quantities. Once you put the numbers in the relationships are less obvious.

If you try the graphical method - you draw the two v-t diagrams. One for Vx and one for Vy. It's a line from (t,v(t)) = (0,-Vi) to (T,+Vf) for each component so it crosses the t axis making two triangles for Vy (and a box for Vx) - you know the area of the second triangle - it's given - and you know the slope of the line. Draw them one above the other and make their time axis coincide - so they both finish at the same place for T.

Your equations will end up consistent with the diagrams which helps you be confident about them as opposed to just using memorized formulae. I figured you'd like this approach because you avoided the projectile equations - which most people would use - favoring your native understanding. Most people would stick to using "up" as positive too. This is good - you'll understand more and it is ultimately less work.

The real trick is to identify where you feel uncertain/unsure about the process - which bits feel intuitively "iffy"? Those are the bits you need to check.

For reasonableness of your answer - you realize that ##v_f## is actually the magnitude of a vector - is that vector pointing in the right direction? Is the magnitude consistent with the components? i.e.

Vfx=5m/s
Vfy = 9.3m/s
Vf = 3.78 m/s

... so Vfx is exactly the same as the total initial velocity - does this seem right?

... Vfy is about twice Vfx - would that be about right? If the apple-core was just dropped from the branch instead of thrown, how fast would it go when it hit? Is that consistent with what you got?

... Vf is the hypotenuse of a right-angled triangle, yet it is smaller that both the other sides... is this right?

... see what I'm talking about?
When you get an answer - think about what it means and how it relates to other things you know.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top