Quick question on Parallel RLC circuit (Conceptual)

AI Thread Summary
In a parallel RLC circuit driven by an AC source, removing the resistor results in a purely reactive circuit where the phase angle can be analyzed through the phasor diagram. The current through the capacitor and inductor will be vertical, with the source voltage horizontal, leading to a phase angle of 0 radians if considering maximum current direction. However, if the phase angle is defined with respect to the voltage, it becomes 90 degrees due to the reactive nature of the circuit. The phase relationship ultimately depends on the values of the inductor and capacitor, determining whether the circuit is leading or lagging. Thus, the removal of the resistor alters the phase angle dynamics significantly.
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Homework Statement


Even conceptual problem in the text:

Consider a standard RLC circuit driven by an AC source in which the elements are in parallel. Construct a phasor diagram and develop an expression for the phase angle θ. Now remove the resistor from the circuit, can you still develop an expression for the phase angle? Why or why not?

The Attempt at a Solution



The first part I was able to do with ease.

If we remove the resistor, then in my diagram I have the current through the capacitor (which lies on the vertical axis, and points upward), the current through the inductor (which lies on the vertical axis, and points downward), and the source voltage ( which lies on the horizontal axis, and points to the right). If we remove the resistor, I argue that the max current will strictly be pointing along the vertical axis and therefore the phase angle will be 0 radians. In addition, if I look at the expression I developed for the phase angle in an RLC circuit in parallel, if I allow R = 0, I again see that the phase angle is necessarily zero.

Am I correct?

Edit - I suppose my question is, when I say phase angle, am I talking about the angle with respect to the voltage? Because if that is the case then my angle is 90 degrees.
 
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AKJ1 said:

Homework Statement


Even conceptual problem in the text:

Consider a standard RLC circuit driven by an AC source in which the elements are in parallel. Construct a phasor diagram and develop an expression for the phase angle θ. Now remove the resistor from the circuit, can you still develop an expression for the phase angle? Why or why not?

The Attempt at a Solution



The first part I was able to do with ease.

If we remove the resistor, then in my diagram I have the current through the capacitor (which lies on the vertical axis, and points upward), the current through the inductor (which lies on the vertical axis, and points downward), and the source voltage ( which lies on the horizontal axis, and points to the right). If we remove the resistor, I argue that the max current will strictly be pointing along the vertical axis and therefore the phase angle will be 0 radians. In addition, if I look at the expression I developed for the phase angle in an RLC circuit in parallel, if I allow R = 0, I again see that the phase angle is necessarily zero.

Am I correct?

Edit - I suppose my question is, when I say phase angle, am I talking about the angle with respect to the voltage? Because if that is the case then my angle is 90 degrees.
Seems right. Removing the resistor will make the circuit purely reactive. Wheather its leading or lagging will be decided by L and C values.
 
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